F(x)=-16x^2+80x+16

Solution for F(x)=-16x^2+80x+16 equation:

(F)=-16F^2+80F+16

We move all terms to the left:

(F)-(-16F^2+80F+16)=0

We get rid of parentheses

16F^2-80F+F-16=0

We add all the numbers together, and all the variables

16F^2-79F-16=0

a = 16; b = -79; c = -16;
Δ = b2-4ac
Δ = -792-4·16·(-16)
Δ = 7265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-\sqrt{7265}}{2*16}=\frac{79-\sqrt{7265}}{32}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+\sqrt{7265}}{2*16}=\frac{79+\sqrt{7265}}{32}
$